10y^2-26y=12

Solution for 10y^2-26y=12 equation:

10y^2-26y=12

We move all terms to the left:

10y^2-26y-(12)=0

a = 10; b = -26; c = -12;
Δ = b2-4ac
Δ = -262-4·10·(-12)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*10}=\frac{-8}{20}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*10}=\frac{60}{20}
=3
$